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Chapter 6: Problem 100
Simplify. $$ \frac{u^{6}+v^{6}+2 u^{3} v^{3}}{u^{3}-v^{3}+u^{2} v-u v^{2}} $$
Short Answer
Expert verified
\(\frac{(u^2 - uv + v^2)^2}{u - v}\)
Step by step solution
01
Factor the Numerator
The numerator can be rewritten as a perfect square. Notice that \(u^6 + v^6 + 2u^3v^3\) is \((u^3 + v^3)^2\). So, rewrite the numerator in factored form: \[(u^3 + v^3)^2\].
02
Factor the Denominator
The denominator \(u^3 - v^3 + u^2v - uv^2\) can be factored by using polynomial identities and common factor. First, factor out common term \(u - v\): \[u^3 - v^3 + u^2v - uv^2 = (u - v)(u^2 + uv + v^2 + uv)\]. Simplify the expression: \[= (u - v)(u^2 + 2uv + v^2)\]. Now further simplify: \[= (u - v)(u + v)^2\].
03
Simplify the Fraction
Now substitute the factored forms back into the original expression: \[\frac{(u^3 + v^3)^2}{(u - v)(u + v)^2} = \frac{(u + v)^2(u^2 - uv + v^2)^2}{(u - v)(u + v)^2}\]. Cancel the common \((u + v)^2\) term from the numerator and the denominator: \[\frac{(u^2 - uv + v^2)^2}{u - v}\].
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomial Factoring
Polynomial factoring is an essential technique in algebra used to simplify complex expressions. It allows us to break down polynomials into simpler parts. This technique is especially useful when dealing with equations and various algebraic expressions.
In the given exercise, both the numerator and the denominator were factored. The numerator \(u^6 + v^6 + 2u^3v^3\) was identified as a perfect square and rewritten as \((u^3 + v^3)^2\). Perfect squares are expressions raised to the power of two, and they simplify our calculations greatly.
To factor the denominator \(u^3 - v^3 + u^2v - uv^2\), we used a combination of factoring by grouping and recognizing common polynomial patterns. It was broken down step-by-step until we arrived at \(u - v)(u + v)^2\). Recognizing these patterns takes practice, but it's a powerful tool for simplifying even the most complicated fractions.
Numerator and Denominator
Understanding the roles of the numerator and the denominator in a fraction is crucial. The numerator is the top part of the fraction, while the denominator is the bottom part. In our given exercise, the numerator was \(u^6 + v^6 + 2u^3v^3\), and we transformed it to \((u^3 + v^3)^2\). The denominator was \(u^3 - v^3 + u^2v - uv^2\), which was simplified to \((u - v)(u + v)^2\).
Factoring both parts allowed us to cancel out common terms easily. When simplifying fractions, always look closely at both the numerator and denominator to identify potential common factors. Simplifying fractions can turn complex algebraic expressions into more manageable forms.
Common Factors
Identifying and canceling common factors is a key step in simplifying algebraic expressions. Common factors are terms that appear in both the numerator and the denominator. In our example, the factored forms of the numerator and the denominator revealed common factors \((u + v)^2\), which significantly simplifies the expression.
By canceling \((u + v)^2\) from the fraction, we reduced it to \((u^2 - uv + v^2)^2 / (u - v)\). Always remember to look for these shared terms because they simplify the expression and make our calculations easier.
Practicing finding common factors in various polynomial expressions will enhance your algebra skills and help tackle more complex problems efficiently.
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